Mathematics-1.Matrices and Determinants with Solution
1.	The value of   is :
	(A)   (  5)		(B) 5  (  5)
	(C) 5  ( + 5)		(D) 5 (  5)
Solution:	L.H.S.= + 
	=5  +5  
	= 5  (  5) + 5   0 = 5  (  5)
	Hence (B) is the correct answer.
2.	  is equal to :
	(A) constant other than zero	(B) zero
	(C) 100	(D) –1997
Solution:	We know that in a determinant, this element in all the rows (columns) are in AP with same or different common difference, the value of the determinant is zero
	Hence (B) is the correct answer.
3.	If a + b +c > 0 and a  b  c  0, then  =   then :  
	(A)  > 0	(B)  < 0
	(C)  = 0	(D) Data insufficient
Solution:	The element of the row are in circular arrangement 
	  =  (a + b + c) { (a  b)2 + (b  c)2 + (c  a)2 } < 0
	Hence (B) is the correct answer.
4.	The determinant   is equal to zero if :
	(A) a, b, c are in A.P.	(B) a, b, c are in G.P.
	(C) a, b, c are in H.P.	(D) none of these
Solution:	 
	R3  R3  (R1  + R2) 
	=  
	This determinant is zero if 
	(a 2 + b  + c) (a c  b2) = 0 
	 b2 = a c 
	 a, b, c are in G.P.
	Hence (B) is the correct answer.
5.	The determinant   is divisible by :
	(A) 1 + x	(B) (1 + x)2
	(C) x2	(D) none of these
Solution:	The given determinant is symmetric in nature
	 = a2 b2 c2 (1 + x)3 + 2 a2 b2 c2  3 a2 b2 c2 (1 + x) 
	= a2 b2 c2 [ (1 + x)3 + 2  3 (1 + x)] 
	= a2 b2 c2 [x3 + 3 x2], divisible by x2
	Hence (C) is the correct answer.
6.	 is equal to :
	(A) a positive number	(B) a negative number
	(C) Zero	(D) none of these
Solution:	    
	Applying R1  R3
	=   +   
	Applying C2  C3
	=      = 0
	Hence (C) is the correct answer.
7.	If f(x) =  ,  then   dx is equal to :
 	(A) 1/4	(B) –1/3
 	(C) 1/2	(D) 1
Solution:	Expanding the given determinant, f (x) = 4 cos3 x  3 cos x 
	= cos 3 x 
	 f (x) dx =    cos 3 x dx 
	=  =  
	Hence (B) is the correct answer.
8.	For positive numbers x, y, z, the numerical value of the determinant   is :
	(A) 0	(B) 1
	(C) 2	(D) none of these 
Solution:	 
	=  	
	=   = 0
	Hence (A) is the correct answer.
9.	 =   is equal to :
	(A) p + q	(B) a + b + c
	(C) x + y + z	(D) 0
Solution:	 
	=      = 0
	Hence (D) is the correct answer.
10.	 is equal to :
	(A) abc	(B) a2b2c2	
	(C) ab + bc + ca	(D) 0
Solution:	 =    
	= a b c =   
	Applying R2  R2  R1 
	R3  R3  R1 
	= a b c   
	= a b2 c2 (a  b) (a  c)  
	= 0, R2 and R3 are identical  
	Hence (D) is the correct answer.
11.	  is equal to :
	(A) 0	(B) 1
	(C) –1	(D) none of these 
Solution:	L.H.S.
	 =  
	=      = 0
	Hence (A) is the correct answer.
12.	If f (x) =   then f (100) is equal to :
	(A) 0	(B) 1
	(C) 100	(D) –100 
Solution:	f (x) =  
	C3  C3  (C1 + C2) 
	=   
	= 0 
	f (100) = 0
	Hence (A) is the correct answer.
13.	 is equal to :
	(A) 1 + åa2	(B) åa2
	(C) (åa)2	(D) åa
Solution:	  
	C1  C1 + b C2 + c C3
	=  
	=  
	C2  C2  b C1, C3  C3  c C1 
	=   = 1 + a2 + b2 + c2
	Hence (A) is the correct answer.
14. 	If A, B, C are the angles of a triangle and  , then D is equal to:
	(A) constant other than zero	(B) not a constant
	(C) 0	(D) none of these 
Solution:	R2  R2  R1 
	R3  R3  R1 
	  
	=   = 0
	Hence (C) is the correct answer.
 
15.	If [.] denotes the greatest integer less than or equal to the real number under consideration and –1  x < 0; 0  y < 1 and 1  z < 2, then the value of the determinant   is :
	(A) [z]	(B) [y]
	(C) [x]	(D) none of these 
Solution:	 1  x < 1  [x] =  1
	0  y < 1  [y] = 0 
	1  z < 2  [z] = 1
	Given determinant equal to   = 1 = [z]
	Hence (A) is the correct answer.
16.	If D =   = 0, then the non zero root of the  equation is :
	(A)  a+b +c	(B) abc 
	(C) – a – b –c 	(D) None of these 
Solution:	C1  C1 + C2 + C3 
	  = 0 
	(x +  a)   = 0  x =  a  b  c
	Hence (C) is the correct answer.
17.	If f (x) =   then the value of  f(x) dx is equal to :
	(A) 0	(B) 1
	(C) 2	(D) none of these
Solution:	f (x) =   =  f (x) 
	f (x) is an odd function  f (x) dx = 0
	Hence (A) is the correct answer.
18.	If A =  , then A2 is equal to 
	(A) unit matrix 	(B) null matrix 
	(C) A 	(D) –A 
Solution:	A2 =   = I3 
19.	If A is the  transpose of a square matrix A, then 
	(A) |A|  |A|	(B) |A| = |A|
	(C) |A| + |A| = 0 	(D) |A| = |A| only when A is symmetric 
Solution:	Value of a determinant remains unattached by interchanging the rows and columns 	    |A| = |AT| 
20.	If I =  ,  J =   and B =  , then B equals 
	(A) I cos + J sin 	(B) I sin + J cos
	(C) I cos – J sin	(D) – I cos + J sin
Solution:	I cos  + J sin  =   +   
	=   = B 
21.	If In is the identity matrix of order n, then (In)–1 
	(A) does not exist  	(B) equal to In 
	(C) equals to O	(D) nIn 
Solution:	In. In = In  In1 = In 
22.	If for a matrix A, A2 + I = O where I is the identity matrix, then A equals 
	(A)  	(B)  
	(C)  	(D)  
Solution:	A2 + I = 0  A2 =  I 
	For A =   =  I 
23.	If A =  , then A40 equals 
	(A)  	(B)  
	(C)  	(D) none of these
Solution:	A = diag (1, 0, 1) 
	 A40 = diag (140, 040, 140) = diag (1, 0, 1) 
24	If A [aij] is a square matrix of order n ´ n such that aii = k for all i, then trace of A is 
equal to 
	(A) kn	(B)  
	(C) nk	(D) none of these
Solution:	Trace of a matrix = sum of principal diagonal elements 
	= k + k + k + … n times = n k 
25.	If A =   and I =  , then the value of k so that A2 = 8A + kI is
	(A) 7	(B) - 7
	(C) 0	(D) 5
Solution:	A2 = 8 A + k I    
	Therefore 8 + k = 1  k =  7 
26.	If A =  , then the value of |adj A| is 
	(A) a27	(B) a9
	(C) a6	(D) a2
Solution:	|adj A| = |A|n1 = (a3)31 = a6 
27.	If A and B are symmetric matrices of order n (A  B), then
	(A) A + B  is skew  symmetric 	(B) A + B  is symmetric
	(C) A + B is a diagonal matrix	(D) A + B  is a zero matrix
Solution:	A = AT amd B = BT 
	(A + B)T = AT + BT = A + B 
	 A + B is symmetric 
28.	If A =   and B =  then AB = 
	(A) A3 	(B) B2 
	(C) O	(D) I
Solution:	A B =   = O 
	
29.	If A =   the  A is 
	(A) Idempotent 	(B) nilpotent 
	(C)symmetric	(D) none of these  
Solution:	A2 =  
	A3 =   = O 
	 A is a nilpotent matrix 
	
30.	If A =  , then 19A–1 is equal to 
	(A) A 	(B) 2A 
	(C)  	(D) A 
Solution:	A1 =   A 
	 19 A1 = A 
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