Chemistry-77.Phase-5-Objective

FACULTY TRAINING TEST PHASE - V CHEMISTRY SCREENING PAPER Time: 1 Hour Maximum Marks: 90 Instructions: 1. This paper consists of 30 QUESTIONS only. 2. Attempt ALL questions. 3. Each correct answer carries 3 marks and each incorrect answer carries –1 mark. 4. Use of Calculator is NOT PERMITTED Name : 00000000000000000 Subject : 00000000000 1. If E0 (Fe3+/Fe) = – 0.036 V & E0 (Fe2+/Fe) = – 0.439 V, the value of E0 (Fe3+, Fe2+/Pt) is (A) – 0.475 V (B) 0.403 V (C) 0.77V (d) 0.986 v 2. The standard reduction potential of 2H2O + 2e–  H2 + 2OH– at 298 K is (A) 0.828 V (B) – 0.828 V (C) 0.414 V (D) – 0.414V 3. If E0 (Fe2+/Fe) = – 0.44V & E0(Pb2+/Pb) = – 0.13V, then adding powdered Pb & Fe to a solution containing 1 M in each of Pb2+ & Fe2+ ions would result into the formation of (A) more of Pb & Fe2+ ions (B) more of Fe & Pb2+ions (C) more of Fe & Pb (D) more of Fe2+ & Pb2+ ions 4. In acidic medium Cr2O72– is converted to Cr3+ when it acts as an oxidising agent. The quantity of electricity required to reduced 0.05 mole of Cr2O72– would be (A) 0.05 F (B) 0.1 F (C) 0.2 F (D) 0.3 F 5. The magnetic moment of Fe2+ ion interms of Bohr magneton is (A) 0.0 (B) 1.73 (C) 2.83 (D) 4.9 6. Of the following complexes, which one is diamagnetic in nature? (A) [CoF6]3– (B) [NiCl4]2– (C) [Ni(NH3)4]2+ (D) [Ni(CN)4]2– 7. Of the following statements, which one is correct? (A) [CoF6]3– is a high spin complex & [Co(NH3)6]3+is a low spin complex (B) [CoF6]3– is a low spin complex & [Co(NH3)6]3+ is a high spin complex (C) Both [CoF6]3– & [Co(NH3)6]3+ are low spin complexes (D) Both [CoF6]3– & [Co(NH3)6]3+ are high spin complexes 8. The edge length of unit cell of sodium chloride is 564 pm. If the size of Cl– ion is 181 pm, the size of Na+ ion would be (A) 383 pm (B) 282 pm (C) 101 pm (D) 202 pm 9. The co-ordination number of metal crystallizing in hexagonal close-packed (hcp) structure is (A) 12 (B) 10 (C) 8 (D) 6 10. Which of the following statements is correct? (A) The co-ordination number of each type of ion in CsCl crystal is 8 (B) A metal that crystallizes in bcc structure has a co-ordination of number of 12 (C) The length of the unit cell in NaCl is 552 pm ( = 95 pm, = 181 pm) (D) The packing fraction for bcc structure is 0.52 11. Which of the following compounds is expected to be coloured (A) Ag2SO4 (B) CuF2 (C) MgF2 (D) CuCl 12. Copper displaces which of the metal from the salt solutions? (A) AgNO3 (B) ZnSO4 (C) FeSO¬4 (D) All of the above 13. Copper sulphate solution reacts with KCN to give (A) Cu(CN)2 (B) CuCN (C) K2[Cu(CN)4] (D) K3[Cu(CN)4] 14. When ammonia is added to a cupric salt solution, the deep blue colour so observed is due to the formation of (A) [Cu(OH)4]2– (B) [Cu(NH3)4]2+ (C) [Cu(H2O)2(NH3)2]2+ (D) [Cu(H2O)4]2+ 15. The oxidation number of Pt in [Pt(C2H4)Cl3]– is (A) +1 (B) +2 (C) +3 (D) +4 16. K4[Fe(CN)6] is called (A) Potassium hexacyanoferrate (II) (B) Potassium hexacyanoferrate (III) (C) Potassium ferricyanide (D) Prussian blue 17. Among the following ions which one has the highest paramagnetism? (A) [Cr(H2O)6]3+ (B) [Fe(H2O)6]2+ (C) [Cu(H2O)6]2+ (D) [Zn(H2O)6]2+ 18. The shape of [Cu(NH¬3)4]2+ is square planar, Cu2+ in the complex is (A) sp3 hybridised (B) dsp2 hybridised (C) sp3d hybridised (D) sp3d2 hybridised 19. AgCl dissolves in NH4OH due to the formation of (A) [Ag(NH4)2]Cl (B) [Ag(NH3)3]Cl (C) [Ag(NH3)2]Cl (D) [Ag(NH3)2OH] 20. Which of the following metals is obtained by leaching its ore with dilute cyanide solution (A) Silver (B) Titanium (C) Vanadium (D) Zinc 21. In the forth-floation process for purification of ores, the ore particles float because (A) They are light (B) Their surface is not easily wetted by water (C) They bear electrostatic charge (D) They are insoluble 22. Of the following metals, which one cannot be obtained by electrolysis of the aqueous solution of its salt is (A) Ag (B) Mg (C) Cu (D) Al 23. Which method of furification is represented by the following equations? Ti + 2I2 (A) Cupellation (B) Pohing (C) Van-Arkel (D) Zone refining 24. Cryolite is the ore of (A) Aluminium (B) Zinc (C) Iron (D) Silver 25. Which of the following metals cannot be extracted by carbon-reduction process? (A) Pb (B) Al (C) Hg (D) Zn 26. How many electrons are there in one coulomb? (A) 6.023  1023 (B) 96500 (C) 1.6  10–19 (D) 6.24  1018 27. How much current is necessary to produce hydrogen gas at a rate of 1200 cc per second at NTP conditions? (A) 96500 ampere (B) 48250 ampere (C) 8.616 ampere (D) 14800 ampere 28. The e.m.f. of half cell PtH¬2 (2 atm) | HCl (a = 0.02) & E0OP= OV is (A) + 0.19 volt (B) + 0.403 volt (C) – 0.409 volt (D) – 0.109 volt 29. Given & . Then (A) Ag+ can be reduced by H2 (B) Ag can oxidise H2(g) to H+ (C) Zn2+ can be reduced by H2 (D) Ag can reduce Zn2+ 30. The complex ion [Co(en)2Cl2]+ exihibits (A) cis-trans isomerism only (B) cis-trans isomerism and linkage isomerism (C) cis-trans isomerism and optical isomerism (D) Optical isomerism and linkage isomerism 6 Answers 1. C 2. B 3. A 4. D 5. D 5. D 6. A 7. C 8. A 9. A 10. B 11. A 12. D 13. B 14. B 15. A 16. B 17. B 18. C 19. A 20. B 21. B 22. A 23. A 24. B 25. D 26. A 27. A 28. A 29. C 30. A

Comments

Post a Comment

Popular posts from this blog

PHYSICS-15-10- 11th (PQRS) SOLUTION

XI (PQRS) PHYSICS REVIEW TEST-5 Select the correct alternative. (Only one is correct) [15 × 3 = 45] There is NEGATIVE marking. 1 mark will be deducted for each wrong answer. Q.31 Two trains, which are moving along different tracks in opposite directions towards each other, are put on the same track due to a mistake. Their drivers, on noticing the mistake, start slowing down the trains when the trains are 300 m apart. Graphs given below show their velocities as function of time as the trains slow down. The separation between the trains when both have stopped, is: (A) 120 m (B) 280 m (C) 60 m (D*) 20 m 1 [Sol: x1 = 2 1 × 10 × 40 = 200 m; x2 = – 2 × 8 × 20 = –80 m  xreletive = x1 + x2 = 280  separation = 300 – 280 = 20 m (D) ] Q.32 One end of a thin uniform rod of length L and mass M is riveted to the centre of a uniform circular disc of radius r and mass 2 M so that the rod is normal to the disc. The centre of mass of the combination from the centre of the disc is at dist
Read more

8-Circular Motion

8.1 (D) The maximum angular speed of the hoop corresponds to the situation when the bead is just about to slide upwards. The free body diagram of the bead is For the bead not to slide upwards. m2 (r sin 45°) cos 45° – mg sin 45° < N (1) where N = mg cos 45° + m2 (r sin 45ยบ) sin 45° (2) From 1 and 2 we get.  = rad / s. 8.2 (C) Let v be the speed of particle at B, just when it is about to loose contact. From application of Newton's second law to the particle normal to the spherical surface. mv2 = mg sin  (1) r Applying conservation of energy as the block moves from A to B.. 1 mv2 = mg (r cos  – r sin ) (2) 2 Solving 1 and 2 we get 3 sin  = 2 cos  8.3 (A) As the mass is at the verge of slipping ∴ mg sin37 –  mg cos37 = m2r 6 – 8 = 4.5   = 3 16 8.4 (B) As when they collide vt  1  72v 2  2 2  25R   R = vt  t =   5R 6v Now angle covered by A =   vt R 11 Put t  angle covered by A = 6 8.5 (C) The acceleration vector s
Read more

4. THEORY-Current Electrictricity

CURRENT ELECTRICITY  1 . ELECTRIC CURRENT (a) Time rate of flow of charge through a cross sectional area is called Current. if q charge flows in time interval t then average current is given by q Iav = t and Instantaneous current i =. lim q  dq t0 t dt (b) Direction of current is along the direction of flow of positive charge or opposite to the direction of flow of negative charge. But the current is a scalar quantity. i i q+ velocity q– velocity SI unit of current is ampere and 1 Ampere = 1 coloumb/sec 1 coloumb/sec = 1A 2 . CONDUCTOR In some materials, the outer electrons of each atom or molecule are only weakly bound to it. These electrons are almost free to move throughout the body of the material and are called free electrons. They are also known as conduction electrons. When such a material is placed in an electric field, the free electrons drift in a direction opposite to the field. Such materials are called conductors. 3 . INSULATOR Another class o
Read more