Computing-02-Assignment

1. A problem to be solved is not subjected to any conditions on variables and is not repetitive in nature. The basic control operation to be used is (a) Sequential (b) Selection (c) Repetitive (d) None of these 2. A computer can execute (a) An algorithm (b) A flow-chart (c) A program (d) None of these 3. A basic control structure always has (a) One entry and two exit points (b) Two entry and one exit points (c) One entry and one exit points (d) Any number of entry and exit points 4. The heart and nerve centre of a computer is (a) Input unit (b) Output unit (c) CPU (d) Memory 5. An algorithm must have at least (a) One input (b) One output (c) One assignment (d) None of these 6. A number of data items are to be read in a problem. The control structure needed is (a) Only sequential (b) Only selection (c) Selection or repetition (d) Sequential or repetition 7. The control structure IF-THEN-ELSE is a (a) Single selection (b) Multiple selection (c) Repetition structure (d) None of these 8. The FOR-DO construct executes the loop at least (a) Once (b) Twice (c) Thrice (d) None of these 9. The control structure CASE-OF is a (a) Single selection (b) Multiple selection (c) Repetition structure (d) None of these 10. If A = 15, B = 22, the value of X after execution of the following pseudo code program is READ A, B IF A  B IF A  10 X  A + B ELSE X  B – A END (a) 7 (b) 15 (c) 22 (d) None of these 11. If A = 7, B = 9, the value of A after execution of the following pseudo-code program is BEGIN INPUT A, B IF A > B TEMP A  B B  A A  TEMP ELSE STOP END (a) 7 (b) 9 (c) 7 + 9 (d) 7 – 9 12. What is the decimal equivalent of binary number 10101 (a) 20 (b) 21 (c) 22 (d) 23 13. The octal equivalent of (101001110)2 is (a) 116 (b) 561 (c) 615 (d) 516 14. What is the decimal equivalent of the octal number 219 (a) 140 (b) 145 (c) 150 (d) 155 15. The value of P by execution of the following algorithm is Step I : If Stop else Go To Step I Output P end (a) 6 (b) 24 (c) 120 (d) 720 16. Study the following algorithm Sum Repeat Sum Sum + (2I + 1) until Then the minimum value of Sum is (a) 36 (b) 49 (c) 140 (d) None of these 17. The statement For To 10 by 20 do S results in (a) 2 cycles (b) 5 cycles (c) 10 cycles (d) None of these

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