DPP-41 to 42 PC English Physical Chemistry

DAILY PRACTICE PROBLEMS (DPP) Subject : Physical/Inorg.Chemistry Date DPP No. 41 to 42 Class : XIII Course : DPP No.41 DPP No.1 Total Marks : 48 Max. Time : 48 min. Single choice Objective ('–1' negative marking) Q.1 to Q.5 (3 marks 3 min.) [15, 15] Multiple choice objective ('–1' negative marking) Q.6 (4 marks 4 min.) [4, 4] Comprehension ('–1' negative marking) Q.7 to Q.8 (3 marks 3 min.) [6, 6] Subjective Questions ('–1' negative marking) Q.9 to Q.10 (4 marks 4 min.) [8, 8] BooSt YoUr PreViouS ConCept Single choice Objective ('–1' negative marking) Q.11 to Q.12 (3 marks 3 min.) [6, 6] Integer Types Questions Short Subjective Questions ('–1' negative marking) Q.13[Q.(i) to Q(iii)] (3 marks 3 min.) [9, 9] 1. Spin only magnetic moment of a complex having CFSE = – 0.6  be: and surrounded by weak field ligands can (1) 1.73 BM (2) 4.9 BM (3) both (1) & (2) (4) None of these 2. Which of the following statements is not correct? (a) [Ni(H O) ]2+ and [Ni(NH ) ]2+ have same value of CFSE 2 6 3 6 (b) [Ni(H O) ]2+ and [Ni(NH ) ]2+ have same value of magnetic moment 2 6 3 6 (1) Only a (2) Only b (3) Both a and b (4) None of these 3. Nitroprusside ion is : A : [FeII(CN) NO+]2– and not B : [FeII(CO) NO]2+. A and B can be differentiated by. (1) estimating the concentration of iron (2) measuring the concentration of CN– (3) measuring the magnetic moment (4) thermally decomposing the compound. 4. It is given that a complex formed by one Ni2+ ion and some Cl– ions and some PPh molecules does not show geometrical isomerism and its solution does not show electrical conductance. Then which is correct about the complex : (1) It is square planar (2) It is tetrahedral (3) It is diamagnetic (4) none of the above is correct 5. The green coloured complex K2[Cr(CN)4(NH3) (NO)] is paramagnetic and its paramagnetic moment (spin only) is 1.73 B.M. Which of the following is correct about it : (i) Its IUPAC name is Potassium amminetetracyanonitrosylchromate () (ii) It IUPAC name is Potassium amminetetracyanonitrosoniumchromate () (iii) Hybridisation state of chromium is sp3d2 (iv) It cannot show geometrical isomerism (v) Hybridisation state of chromium is d2sp3 (vi) It can show linkage isomerism (1) (ii), (iii),(iv) (2) (i),(iii), (vi) (3) (i), (v) (4) (ii), (v), (vi) 6. Which are correct statements ? (1) [Ag(NH ) ]+ is linear with sp hybridised Ag+ ion. (2) NiCl 2– , VO 3– and MnO – have tetrahedral geometry 4 4 4 (3) [Cu(NH ) ]2+ , [Pt(NH ) ]2+ and [Ni(CN) ]2– have dsp2 hybridisation of the metal ion 3 4 3 4 4 (4) Fe(CO)5 have bipyramidal structure with dsp hybridised iron. 3 Passage : (Q.7 to Q.8) Read the following passage based on Applications of crystal field theory to explains magnetic and spectral properties of complexes carefully and answer the questions. With the help of CFT number of unpaired electron in a compound can be calculated and we can calculate its paramagnetic moment(due to spin only), by the formula : ยต = Bohr magneton (BM). where n is the number of unpaired electron in the complex. For spectral analysis the separation between t and e orbitals, called ligand field splitting. Parameter  (for octahedral complexes) should be known to us, which can be easily calculated by observing the absorption spectrum of one electron complex. Figure shows the optical absorption spectrum of the d1 hexaaquatitanium(III) ion [Ti(H O) ]3+. The CFT assigns the first absorption maximum at 20,300 cm–1 to the transition e  t . For 2 6 g 2g multielectronic(d2 to d10) system, the calculation of  by absorption spectrum is not that easy as the absorption spectrum will also be affected by electron-electron repulsions. 7. The crystal field stabilization energy (CFSE) for complex given in the passage, [Ti(H O) ]3+ will be 2 6 (in kJ/mol) (1) 243 kJ/mole (2) 97 kJ/mole (3) 194 kJ/mole (4) 143 kJ/mole 8. The magnetic moments of following, arranged in increasing order will be (atomic number of Co = 27) (1) Co3+ (octahedral complex with a strong field ligand) (2) Co3+ (octahedral complex with a weak field ligand) (3) Co2+ (tetrahedral complex) (4) Co2+ (square planar complex) (1) 1 > 2 > 3 > 4 (2) 2 > 3 > 4 > 1 (3) 3 > 2 > 4 > 1 (4) 2 > 4 > 3 > 1 9. In each of the following pair of complexes, choose the one that absorbs light at a longer wave length. (1) [Co(NH ) ]2+ , [Co(H O) ]2+ (2) [FeF ]3– , [Fe(CN) ]3– (3) [Cu(NH ) ]2+ , [CuCl ]2– 3 6 2 6 6 6 3 4 4 10. Observed (expermiental) lattice energies (in KJ/mol) of octahedrally coordinated crystals of VO and FeO are – 3917 and – 3923 respectively. The lattice energies of these crystals in the absence of CFSE are – 3691 and – 3856 kJ/mol respectively. Assuming that oxide ion (O2–) is a weak field ligand, calculate CFSE value of V2+ and Fe2+ ion. BooSt YoUr PreViouS ConCept 11. Ca3(PO4)2(s) and H3PO3(s) contains same number of 'P' atom then the ratio of oxygen atom in the two compounds respectively is : 8 (1) 3 2 (2) 3 4 (3) 3 (4) 3 12. 17 g of AgNO3 solution is mixed with 400 ml of 0.2 M HCl solution then how many gram of AgCl will be precipitated : [Ag = 108, Cl = 35.5, N = 14, O = 16] (1) 16.7 (2) 14.35 (3) 11.48 (4) 36.5 Integer Answer Type 13. This section contains 3 questions. The answer to each of the questions is a single digit integer, ranging from 0 to 9. (i) Find out the number of 3d electrons occupied in t orbitals of hydrated Cr3+ ion (octahedral). (ii) How many Cr—O bonds are equivalent in dichromate anion ? (iii) CrO42– + 2H+ + 2H2O2  CrO5 + 3H2O How many peroxide linkages are found in the structure of CrO5 ? DPP No.42 DPP No.2 Total Marks : 45 Max. Time : 45 min. Single choice Objective ('–1' negative marking) Q.1 to Q.5 (3 marks 3 min.) [15, 15] Multiple choice objective ('–1' negative marking) Q.6 to Q.8 (4 marks 4 min.) [12, 12] Comprehension ('–1' negative marking) Q.9 to Q.11 (3 marks 3 min.) [9, 9] BooSt YoUr PreViouS ConCept Comprehension ('–1' negative marking) Q.9 to Q.11 (3 marks 3 min.) [9, 9] 1. Which of the following is true : (1) [Zn(Cl)2 (NH3)2] will exist in cis and trans forms (2) [Pt(Br) (Cl) (NH3) (Py)] is an optically active compound (3) The brown ring complex [Fe(H O) NO+]2+ is paramagnetic 2 5 (4) All the above are true 2. Which of the following is true about the complex [PtCl2(NH3)(OH2)] ; [Atomic no. of Pt = 78] (i) It will have two geometrical isomeric forms, cis and trans (ii) The hybridisation state of Pt() is sp3 (iii) It is a square planar complex (iv) It is a diamagnetic complex (v) It can show hydrate isomerism (vi) It is a tetrahedral complex (1) (i), (iii),(iv) (2) (ii),(iv),(v) (3) (ii),(v),(vi) (4) (i),(v),(vi) 3. The octahedral complex [Rh(NO ) (SCN) (en) ]+ can exist in a total number of isomeric forms including 2 2 stereoisomers : (1) 2 (2) 4 (3) 8 (4) 12 4. Total number of geometrical isomers of Ma3 b3 type of octahedral complex are (1) Two (2) four (3) Six (4) Zero 5. STATEMENT -1 : Tetrahedral complexes do not show geometrical isomerism STATEMENT -2 : All the bond angles in tetrahedral geometry are 109.5°. (1) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1. (2) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1 (3) Statement-1 is True, Statement-2 is False (4) Statement-1 is False, Statement-2 is True (5) Statement-1 is False, Statement-2 is False 6. Which is/are correct statement (s) ? (1) [Co(en)3] [Cr(CN)6] will display coordination isomerism. (2) [Mn(CO)5(SCN)] will display linkage isomerism. (3) [Co(NH3)5(NO3)]SO4 will display ionisation isomerism (4) None is correct. 7. Which of the following statement(s) is(are) correct ? (1) [Fe(CN) ]3– and [Co(C O ) ]3– are inner orbital complexes. 6 2 4 3 (2) [FeF ]3– and [CoF ]3– are outer orbital complexes. 6 6 (3) [Ni(NH ) ]2+ is an outer orbital complex. (4) [Fe(H O) ]3+ is outer orbital complex with five unpaired electrons. 2 6 8. Which are correct statements ? (1) [Ag(NH ) ]+ is linear with sp hybridised Ag+ ion. (2) NiCl 2– , VO 3– and MnO – have tetrahedral geometry 4 4 4 (3) [Cu(NH ) ]2+ , [Pt(NH ) ]2+ and [Ni(CN) ]2– have dsp2 hybridisation of the metal ion 3 4 3 4 4 (4) Fe(CO)5 have bipyramidal structure with dsp hybridised iron. 3 BooSt YoUr PreViouS ConCept Comperhension : (Q.9 to Q.11) Many times two different solutions are mixed together to get desired concentration in different volume ratio. To 100 ml of 5 M NaOH solution (density 1.2 g/ml) were added 200/3 ml of another NaOH solution which has a density of 1.5 g/ml and contains 20 mass percent of NaOH. Aluminium reacts with this (final) solution according to the following reaction. Al + NaOH + H2O  NaAlO2 + H2 (At.wt. Al = 27, Na = 23, O = 16, H = 1) 9. What is the concentration of resulting NaOH solution obtained by mixing above two NaOH solutions : (1) 5 M (2) 3 M (3) 6 M (4) 2 M 10. What is the maximum volume of H2(g) liberated at STP when Al reacts with the complete solution as in the above reaction : (1) 22.4 L (2) 44.8 L (3) 67.2 L (4) 33.6 L 11. How much volume of the above solution is needed for the complete reaction with 54 g of Al : 2500 (1) 3 500 ml (2) 3 1000 ml (3) 3 ml (4) None of these ANSWER KEY DPP No.39 1. (3) 2. (4) 3. (2) 4. (4) 5. (3) 6. (2) 7. (4) 8. Co (H2O)4 (NO2)3 [Co(H2O)3 (NO2)3]. H2O does not conduct electricity because no ion is generated in aq. sol. [Co (H2O)4 (NO2)2] NO2 will conduct electricity. 9. [Co(NH3)4Cl2]Cl Tetramminedichloridocobalt(III) chloride. 10. (i) K4 [Fe(CN)6] will produce 5 ions while K3 [Fe(CN)6] will produce 4 ions in aq. sol. so, higher molar conductivity. (ii) [Pt(NH3)2CI2] produce no ions but [Pt(NH3)6]CI4 produce 5 ions in aqueous sol. so, higher molar conductivity. (iii) [CoCI3(NH3)3] will not produce any ion in aq. sol. so, conductivity. is zero. 11. [Co(NH3)6] CI3 > [Co(NH3)5 CI]CI > [Co(NH3)3 CI3] More no. of ion present in aqueous solution quantivity increase. 12. CoCl3.4NH3 Since only one CI– ion is precipiteated by Ag+ ion. This implies that only one CI– ion outside coordination sphere.  [Co(NH3)4CI2]CI H3N H3N CI CI Trans NH3 NH3 + CI H3N NH3 NH3 Cis + CI NH3 ANSWER KEY DPP No.40 1. (2) 2. (3) 3. (1) 4. (3) 5. (3) 6. (3) 7. (2) 8. (1) 9. (3) 10. (2) 11. (2)

Comments

Popular posts from this blog

Planning to start your own coaching institute for JEE, NEET, CBSE or Foundation? Here's why not to waste time in developing study material from scratch. Instead use the readymade study material to stay focused on quality of teaching as quality of teaching is the primary job in coaching profession while study material is secondary one. Quality of teaching determines results of your coaching that decides success & future of your coaching while good quality study material is merely a necessary teaching aid that supplements your teaching (video in Hindi)

Physics-30.24-Physics-Solids and Semiconductors

Physics-31.Rotational Mechanics