CHEMISTRY-17-09- 11th (PQRS) Space

REVIEW TEST-4 Class : XI Time : 100 min Max. Marks : 75 General Remarks: INSTRUCTIONS 1. The question paper contains 16 questions and 23 pages. All questions are compulsory. 2. Write your answer(s) in the space given at the end of each question. Otherwise Marks will not be awarded. 3. Each question should be done only in the space provided for it, otherwise the solution will not be checked. 4. Use of Calculator, Log table and Mobile is not permitted. 5. Legibility and clarity in answering the question will be appreciated. 6. Put a cross ( × ) on the rough work done by you. Name Father's Name Class : XI Batch : P B.C. Roll No. Invigilator's Full Name USEFUL DATA Atomic weights: Al = 27, Mg = 24, Cu = 63.5, Mn = 55, Cl = 35.5, O = 16, H = 1, P = 31, Ag = 108, N = 14, Li = 7, I = 127, Cr = 52, K=39, S = 32, Na = 23, C = 12, Br = 80, Fe = 56, Ca = 40, Zn = 65.4, Pt = 195 Important Instruction: Tampering with the answer sheet or changing the answers, after the answer sheet is evaluated will be strictly penalized. For Office Use ……………………………. Total Marks Obtained………………… Q.No 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 Marks Q.1 A packet of an aritifical sweetner contains 45.75 mg of saccharin which has the structural formula How manymoles & molecules of saccharin are contained in 45.75 mg of saccharin? How many hydrogen atoms? [NA = 6 × 1022] [3] Q.2 The subshell that arises after f sub-shell is called g sub-shell. (a) How many g orbitals are present in the g sub-shell (b) In what principal electronic shell (n) would the g sub-shell first occur and what is the total number of orbitals in the shell. [3] Q.3 For a real gas (mol. mass = 30) if density at critical point is 0.40 g/cm3 and its Tc = 2105 821 K, then calculate Vander Waal's constant a (in atm L2mol–2). [3] Q.4 The percentage by volume of C3H8 in a gaseous mixture of C3H8, CH4 and CO is 39. When 100 ml of the mixture is burnt in excess of O2. Find volume (in ml) of CO2 produced. [3] Q.5 The angular momentum of an electron in a Bohr's orbit of H-atom is 3.1652×10–34 kg-m2/sec. Calculate the wavenumber in terms of Rydberg constant (R) of the spectral line emitted when an electron falls from this level to the ground state.[Use h = 6.6 × 10–34 Js] [3] Q.6 Use the Heisenberg's Uncertainity Principle to calculate the uncertainity (in meters) in the position of a honeybee weighing 0.70 g and travelling at a velocity of 0.85 m/s. Assume the uncertainity in the velocity is 0.1 m/s.[Use h = 6.6 × 10–34 Js] [3] Q.7 If Pd v/s P (where P denotes pressure in atm and d denotes density in gm/L) is plotted for H2 gas (ideal gas) at a particular temperature. If  d (Pd) = 10, then find the temperature in °C.  dP P8.21atm [3] Q.8 Radiation corresponding to the transition n = 4 to n = 2 in hydrogen atoms falls on a certain alkali metal (work function = 2.0 eV). Calculate maximum kinetic energy (in eV) of the photoelectrons. [4] Q.9(a) What is the shortest wavelength of line (in nanometers) in the Lyman series of He+ spectrum [use R = 1.097 × 10–2 nm–1] (b) Which is denser at the same temperature and pressure, dry air or air saturated with water vapour? Justify in brief. [2+2] Q.10 For the reaction 2NH3(g) — N2(g) + 3H2(g). What is the % of NH3 converted if the mixture diffuses twice as fast as that of SO2 under similar conditions [5] Q.11 Urea (H2N–CO–NH2) is manufactured on large scale by passing CO2(g) through ammonia solution followed by crystallization. CO2 for the above reaction is prepared by combustion of hydrocarbon. If combustion of 236.11 kg of a saturated hydrocarbon (CnH2n+2) produces as much CO2 as required for production of 1000 kg urea, deduce molecular formula of hydrocarbon. 2NH3 + CO2  NH2CONH2 + H2O [5] Q.12(a) Arrange the correct order of increasing wavenumber of the following radiations I.R., U.V., radiowaves, X-rays and visible light (b) Match the column Column I Column II (A) Lyman series (P) Visible region (B) Humphrey series (Q) Ultraviolet region (C) Paschen series (R) Infrared region (D) Balmer series (S) Far infrared region (c) Two flasks Aand B of equal volumes maintained at temperature 300 K and 600 K contain equal mass of H2 and CH4 respectively. Calculate the ratio of total translational kinetic energy of gas in flask A to that of flask B. [2+2+2] Q.13 2.5 g of a sample containing Na2CO3, NaHCO3 and some non-volatile impurity on gentle heating loses 12.4 % of its weight. Residue is dissolved in 100 ml water and its 10 ml portion required 15 ml of 0.1 M aqueous solution of BaCl2 for complete precipitation of carbonates. Determine mass % of Na2CO3 in the original sample. 2NaHCO3  Na2CO3 + CO2 + H2O Na2CO3 + BaCl2  2NaCl + BaCO3  [6] Q.14(a) At 273 K and 8 atm pressure, the comprassibility factor for a gas is 0.8. Calculate the volume of 1 milli moles of gas at this temperature and pressure. (b) From his exceptional 'mathematical skills', Mr. Gupta was able to obtain the following expression for  (the amplitude of electron wave) by solving Schrodinger equation. However he wants to know those 'r' where probability of finding the electron is zero. Since he is 'exhausted' in his work, help himto find the values of 'r' acting as nodes(  2 = zero). 1  Z 3 / 2     (  1)( 2  8  12 ) e / 2 16 4  a 0  where a0 & Z are the constant in which answer can be expressed &   2Zr a 0 [3+5] Q.15(a) Calculate the ratio of time periods in first and third orbits of hydrogen atom. (b) The electron in the first excited state (n1 = 2) of H-atom absorbs a photon and is further excited (n2).The Debroglie wavelength of the electron in this excited state is 1340 pm. Find the value of n2. [3+5] Q.16 The apparatus shown consists of three temperature jacketed 1 litre bulbs connected by stop cocks. Bulb A contains a mixture of H2O(g), CO2(g) and N2(g) at 27°C and a total pressure of 547.2 mm Hg. Bulb B is empty and is held at a temperature –23°C. Bulb C is also empty and is held at a temperature of –173°C. The stopcocks are closed and the volumes of lines connecting the bulbs is zero. Given: CO2(g) converted into CO2(s) at –78°, N2(g) converted into N2(s) at –196°C & H2O(g) converted into H2O(s) at 0°C. [Use R = 0.08 atm-litre/mole·K] (a) The stopcock betweenA & B is opened and the system is allowed to come to equilibrium. The pressure in A & B is now 228 mmHg. What do bulbs A & B contain? (b) How many moles of H2O are in system? (c) Both stopcocks are opened and the system is again allowed to equilibrium. The pressure throughout the system is 45.6 mmHg. What do bulbs A, B and C contain? (d) How many moles of N2 are in the system? [8]

Comments

Post a Comment

Popular posts from this blog

PHYSICS-15-10- 11th (PQRS) SOLUTION

XI (PQRS) PHYSICS REVIEW TEST-5 Select the correct alternative. (Only one is correct) [15 × 3 = 45] There is NEGATIVE marking. 1 mark will be deducted for each wrong answer. Q.31 Two trains, which are moving along different tracks in opposite directions towards each other, are put on the same track due to a mistake. Their drivers, on noticing the mistake, start slowing down the trains when the trains are 300 m apart. Graphs given below show their velocities as function of time as the trains slow down. The separation between the trains when both have stopped, is: (A) 120 m (B) 280 m (C) 60 m (D*) 20 m 1 [Sol: x1 = 2 1 × 10 × 40 = 200 m; x2 = – 2 × 8 × 20 = –80 m  xreletive = x1 + x2 = 280  separation = 300 – 280 = 20 m (D) ] Q.32 One end of a thin uniform rod of length L and mass M is riveted to the centre of a uniform circular disc of radius r and mass 2 M so that the rod is normal to the disc. The centre of mass of the combination from the centre of the disc is at dist
Read more

8-Circular Motion

8.1 (D) The maximum angular speed of the hoop corresponds to the situation when the bead is just about to slide upwards. The free body diagram of the bead is For the bead not to slide upwards. m2 (r sin 45°) cos 45° – mg sin 45° < N (1) where N = mg cos 45° + m2 (r sin 45ยบ) sin 45° (2) From 1 and 2 we get.  = rad / s. 8.2 (C) Let v be the speed of particle at B, just when it is about to loose contact. From application of Newton's second law to the particle normal to the spherical surface. mv2 = mg sin  (1) r Applying conservation of energy as the block moves from A to B.. 1 mv2 = mg (r cos  – r sin ) (2) 2 Solving 1 and 2 we get 3 sin  = 2 cos  8.3 (A) As the mass is at the verge of slipping ∴ mg sin37 –  mg cos37 = m2r 6 – 8 = 4.5   = 3 16 8.4 (B) As when they collide vt  1  72v 2  2 2  25R   R = vt  t =   5R 6v Now angle covered by A =   vt R 11 Put t  angle covered by A = 6 8.5 (C) The acceleration vector s
Read more

4. THEORY-Current Electrictricity

CURRENT ELECTRICITY  1 . ELECTRIC CURRENT (a) Time rate of flow of charge through a cross sectional area is called Current. if q charge flows in time interval t then average current is given by q Iav = t and Instantaneous current i =. lim q  dq t0 t dt (b) Direction of current is along the direction of flow of positive charge or opposite to the direction of flow of negative charge. But the current is a scalar quantity. i i q+ velocity q– velocity SI unit of current is ampere and 1 Ampere = 1 coloumb/sec 1 coloumb/sec = 1A 2 . CONDUCTOR In some materials, the outer electrons of each atom or molecule are only weakly bound to it. These electrons are almost free to move throughout the body of the material and are called free electrons. They are also known as conduction electrons. When such a material is placed in an electric field, the free electrons drift in a direction opposite to the field. Such materials are called conductors. 3 . INSULATOR Another class o
Read more