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preparation, properties and reactions. Alkanes - Conformations : Sawhorse and Newman projections (of ethane); Mechanism of halogenation of alkanes. Alkenes - Geometrical isomerism; Mechanism of electrophilic addition: addition of hydrogen, halogens, water, hydrogen halides (Markownikoff’ s and peroxide effect); O zonolysis, oxidation, a nd polymerization. Alkynes - Acidic character; Addition of hydrogen, ha logens, water a nd hydrogen halides; Polymerization. Aromatic hydrocarbons - Nomenclature, benzene - structure and aromaticity; Mechanism of electrophilic substitution: halogenation, nitration, Friedel – Craft’s alkylation and acylation, directive influence of functional group in
mono-substituted benzene.
HYDROCARBONS AND THEIR CLASSIFICATIONS
Compounds of only Carbon and Hydrogen are called hydrocarbons. They are parent organic compounds and all other organic compounds have been derived by replacing one or more H atoms from hydrocarbon.
Hydrocarbons
CHAPTER INCLUDES
Alkane
Alkene
Acyclic
(open chain hydrocarbon)
Alicyclic
Cyclic
Aromatic
CH3
Alkyne
Aromatic
hydrocarbons
Saturated hydrocarbon/
Alkanes/Paraffins
Unsaturated
hydrocarbons (having= and ≡)
(cycloalkanes)
i.e., ,
etc. i.e.,
,
Toluene
ALKANES
Methods of Preparation :
Reactions where number of carbon atoms are increased
Wurtz Reaction
2R − X + 2Na ⎯⎯dry⎯eth⎯er →R − R + NaX
Here other metals in the finely divided state may also be used such as Cu, Ag etc.
Methane cannot be prepared by this method.
Only symmetrical alkane can be prepared by this method in good yield.
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Corey-House Synthesis:
R - X + Li ⎯⎯→RLi + LiX
RLi + CuI ⎯⎯→R2LiCu
(a)
(b)
R2LiCu + 2R − X ⎯⎯→ 2R − R + LiX + CuX R2LiCu + 2R′ − X ⎯⎯→ 2R − R′ + LiX + CuX
etc.
It can be used for preparing both symmetrical and unsymmetrical alkanes.
Kolbe’s Electrolytic Decarboxylation
2RCOONa (aq) ⎯⎯ele⎯ct⎯rol⎯yti⎯c →R - R + 2NaOH + 2CO2 + H2
Mechanism:
RCOONa RCOO– + Na+ 2H O 2H+ + 2OH–
Anodic Reaction
2RCOO– 2RCOO• + 2e–
2RCOO• R - R + 2CO
Cathodic Reaction
2H+ + 2e– H
Methane cannot be prepared by this method
Unsymmetrical hydrocarbon (alkane) cannot be prepared
Reactions where number of carbon atoms are retained
Sabatier - Sanderen’s Reduction
H H
C = C
+ H2
Raney Ni
200 - 300°C
C – C
| |
H H
– C ≡ C – + 2H
Raney Ni
200 - 300°C
| |
— C — C —
| |
H H
Reduction of Alkyl Halides
R − X + Zn ⎯⎯H⎯Cl →R − H+ HX
Zn – Cu and C2H5OH or Na and alcohol can also be used
4R–X + LiAlH4 ⎯⎯→ 4RH + LiX+AlX
This is a nucleophilic substitution reaction with the nucleophilic H– coming from LiAlH .
R – X + (n – C4 H9)3SnH R – H + (n –C4H9)3SnX.
Reduction of Alcohols, Aldehydes, Ketones and Carboxylic Acids with HI/Red P.
ROH + 2HI
R
⎯⎯Re d⎯⎯P →R − H + I2 + H2O
150°C
(b)
H
R1
C = O + 4HI
2H 2H
Red P 150°C
R–CH3 + H2O + 2I2
C = O
R2
+ 4HI
⎯⎯Re d⎯P →
150°C
R1 – CH2
R2
+ H2O + 2I2
2H
R — C
2H O
+ 6HI ⎯⎯Red⎯P →R − CH3 + 2H2O + 3I2
150°C
OH H
Clemmensen’s Reduction
CH 3 − C − H + 4H ⎯ ⎯Zn−⎯Hg⎯/ H⎯Cl → CH 3 − CH 3 + H 2 O
|| Δ
O
R1 − C− R2 + 4H ⎯⎯Zn−⎯Hg⎯/ H⎯Cl →H2O + R1 − CH2 − R2
||
O
Clemmensen’s reduction should not be used when the carbonyl compound has a basic end in it.
Wolf-Kishner’s Reduction:
R1 – C– H + NH2
||
NH2
→ R – C = N − NH2
|
H2O
KOH+Glycol 453 k − 473 k
R – CH3 + N2
O
CH3 – C– C2H5 + NH2 – NH2
||
O
H
CH3 C H
Hydrazone
C=N–NH2 +H
O ⎯⎯KO⎯H⎯+ ⎯Gl⎯yc⎯o⎯l → CH3CH2C2H5 + N2
2 453 K –473 K
2 5 Hydrazone
This reaction should not be used when the carbonyl compound has an acidic end in it.
(a) Using Grignard’s Reagent
R - X + Mg
⎯⎯eth⎯er → RMgX
RMgX + H – OH R – H + MgX(OH)
+ H – NH2 R – H + MgX(NH2)
+ H – OR1 R – H + MgX(OR1)
+H–O–C–R′
||
O
R–H +| MgX (O–C–R′)
||
O
(b) Using Alkyl lithium compound
R1 NH + R–Li (R1NH) Li + R – H.
Reaction where number of carbon atom are decreased Sodalime Decarboxylation
RCOONa + NaOH
CaO
630 k
R – H + Na2CO3
CH3
CaO
CH—CH —COONa + NaOH
CH3
CH—CH + Na CO
2
CH3
630 k
CH3
3 2 3
Some other methods of preparation
Preparation of Methane from carbides
(a) Al4C3 + 12H2O 4Al(OH)3 + 3CH4
Be2C + 4H2O 2Be(OH)2 + CH4
Methane from carbon monoxide
CO + 3H2
⎯⎯Ni +⎯C →
250°C
CH4
+ H2O
This is also called Sabatier Sanderen’s reduction
Physical Properties Boiling Point (B.P.)
B.P. increases with the increase of molecular mass. Among the isomers, straight chain alkane have higher
b.p. than branched chain alkane.
Melting Point (M.P.)
The melting points do not show regular variation with increase in molecular size. The even number members have higher m.p. as compared to next alkanes with odd number of carbon atoms (ALTERATION EFFECT).
Solubility
They are soluble in non polar solvents but insoluble in polar solvents such as water.
Chemical Properties
Alkanes are generally inert towards acids, bases, oxidising and reducing agents but they give following reactions:
Halogenation. Alkanes undergoes substitution reaction with halogen. Cl2 and Br2 only in presence of ultra violet light or high temperature (573 – 773K). But in presence of direct sunlight reaction is as
CH + 2Cl ⎯⎯⎯⎯⎯⎯→ C + 4HCl
direct sunlight
CH4 + Cl2 ⎯⎯h⎯ν → CH3Cl + HCl CH3Cl + Cl2 ⎯⎯h⎯ν → CH2Cl2 + HCl CH2Cl2 + Cl2 ⎯⎯h⎯ν → CHCl3 + HCl CHCl3 + Cl2 ⎯⎯h⎯ν → CCl4 + HCl
Decreasing order of reactivity of halogens towards alkanes. F2 > Cl2 > Br2 > I2
CH – CH – CH + Cl
298 K
CH CH – CH + CH CH CH –Cl
3 2 3
CH3
2 Light 3
Cl
3 3 2 2
CH – C – H + Cl
298 K
(CH ) C – Cl + (CH ) CHCH Cl
3
CH3
2 Light
3 3 3 2 2
Similarly
CH3
CH – C – H + Br
298 K
(CH ) C – Br + (CH ) CH–CH Br
3
CH3
2 Light
3 3 3 2 2
99% 1%
General mechanism : Halogenation of alkanes takes place in 3 steps :
Chain initiation steps : X + X
sunlight
Propagation :
Termination
R − H + X∙ ⎯⎯→R∙ + HX R∙ + X − X ⎯⎯→RX + X∙
X∙ + X∙ ⎯⎯→ X − X
R∙ + R∙ ⎯⎯→R − R
R∙ + X∙ ⎯⎯→R − X
Among these three steps, propagation step is rate determing step.
The relative rates of abstraction of various types of hydrogen follow the order : 3ºC : 2ºC : 1ºC
Chlorination → 5 : 3.8 : 1
Bromination → 1600 : 82 : 1
Liquid phase For higher alkanes – Fuming HNO3, at 413 K
Nitration :
e.g., :
C6H13 – H + HONO2
C6H13NO2 + H2O
Vapour phase For lower alkanes – conc. HNO3, at 670-750 K
e.g., :
CH3 −
NO2 ⎯⎯→CH3NO2 + H2O
Oxidation : Alkanes undergo oxidation under special conditions to yield a variety of products.
(a)
(b)
2CH + O ⎯⎯⎯C⎯u ⎯⎯→ 2CH OH
573 / 1100 atm
CH + O ⎯⎯⎯⎯→HCHO + H O
Mo2O3
2R – CH + 3O
Manganese acetate
O
2R – C – OH + 2H O
3 2 373-430 K 2
or Ag2O
Isomerization : In presence of Anhy. AlCl3 + HCl or AlBr3 + HBr, straight chain alkanes, get converted in branched alkane.
CH – CH
CH
CH
AlCl3 + HCl
CH3
CH – CH – CH
3 3 3 3
200ºC, 35 atm 3 3
CH (CH ) – CH AlCl3 + HCl
CH3 – CH – CH2 – CH2 – CH3 + CH3
CH3 – CH2 – CH– CH2 – CH3 CH3
2-methyl pentane 3-methyl pentane
Aromatization : Alkanes having minimum 6 or more carbons when heated at 773 K under high pressure (10-20 atm) in presence of Cr2O3, V2O3, Mo2O3 supported on Alumina gets converted into aromatic hydrocarbon.
CH ( CH ) CH Cr2O3
+ 4H ↑
3 2 4 3
773K, 10-20 atm
2
Benzene
n-heptane Cr2O3 773K, 10-20 atm
Reaction with steam :
CH4 + H2O ⎯⎯Ni → CO + 3H2
Conformations of Alkanes
CH3
Toluene
+ 4H2↑
Conformations isomers/conformers are compounds which arises due to rotation around C–C. In fact C–C rotation is hindered by an energy barrier of 1 to 20 kJ × mol–1. There are infinite number of conformers possible. Out of infinite number of conformers extremes can be discussed as
Conformers of ethane :
H H H H H
H H
H
H H H H H H
H H H H
Eclipsed
Staggered
Eclipsed Staggered
Sawhorse projection Newmann projection
It may be noted that one extreme conformation of ethane can be converted into other extreme conformer by rotation of 60º about C–C bond.
Conformers lying between two extreme are called skew conformations.
0 60º 120º 180º
dihedral angle
Staggered> Eclipsed Decreasingorder of stability
Conformers of propane :
CH3
H H
CH3
H
H
H H H H H H
Eclipsed Staggered
Conformers of Butane :
CH3
CH3
CH3
CH CH3
H H H
CH3 H 3
60º
60º
H
60º
H
H H
CH3
(I)
H CH3
H
(II)
H H
H
(III)
H H H
(IV)
Staggered
Partially eclipsed
Gauche
(V)
Gauche
CH3
H
60º
Fully eclipsed
CH3 H
CH3
H H H
(VI)
Partially eclipsed
Stability order : I > III ≈ V > II ≈ VI > IV
ALKENES
Alkene have the structural unit
〉C = C〈 . The carbon atoms carrying the unsaturation are sp2 hybridized
with the p orbital laterally overlaping to form π-bonds. They have the general formula CnH2n. They are isomeric with cycloalkanes e.g. – C4H8
CH3 – CH2 – CH = CH2
Butene
Nomenclature :
CH2 CH2
CH2 CH2
Cyclobutane
The IUPAC rules for naming alkenes are similar in many respects to those for naming alkanes. Hence few solved examples are taken.
1 2 3 4 5
(i)
CH3 – CH = CH– CH2 – CH3
2 - pentene
CH3
C2H5
CH3– C = CH– CH2 – CH – CH2–CH2–CH3 1 2 3 4 5 6 7 8
5-Ethyl–2–methyl–2–octene
Alkene – H = Alkenyl
e.g., CH2 = CH– ethenyl (Vinyl group); CH2 = CH – CH2 – propenyl (Allyl group)
e.g., CH2 = CH – Cl - Vinyl chloride; CH2 = CH–CH2–OH Allyl alcohol
Preparations of Alkenes
From Alcohols
By heating alcohol with H2SO4 or H3PO4 at 170°C.
CH – CH
OH
95% H2SO4 CH
= CH
3 2
Mechanism :
170°C 2 2
1st step : H2SO4
⎯⎯→
H+ + HSO –
2nd step : CH – CH – OH + H+ +
3 2
3rd step : CH – CH ⊕ H
CH3 – CH2 – OH2
⊕
CH3 – CH2 + H2O
4th step :
+ CH2 – CH2
H
–
CH2 = CH2 +H2SO4
HSO4
Here the 3rd step i.e. formation of carbocation is rate determining step.
The ease of dehydration of alcohols depends on the stability of carbocations formed. Hence the order of reactivity of alcohols is ter–> sec–> pri–> CH3 – OH because the incipient carbonium ion stability is ter–> sec–> pri–> CH +.
Hydride shift or
Example (Hydride shift)
CH3 – CH – CH – CH3 CH3 OH
Mechanism :
H2SO4
170°c
+
CH3 – C = CH2 – CH3 +
CH3
(Major)
CH2 = C – CH2 – CH3
CH3
(Minor)
CH3 – CH – CH – CH3 + H CH3 O.. H
H
CH3– C – CH – CH3
CH3 – CH – CH – CH2 CH3 OH2
+ +
CH3 – C – CH – CH3 CH3 – C – CH2 – CH3
CH3 CH3
sec-carbocation ter-carbocation
(Less stable) (More stable)
H (a) CH – C = CH – CH
(A)
H – CH2 – C – CH – CH3 CH3
CH3
CH2 = C – CH2 – CH3 CH3
(B)
Dehydration of alcohols follow Saytzeff’s rule.
Hence (B) product is maximum.
Saytzeff’s Rule: It states that “During dehydration of alcohols and dehydrohalogenation of alkyl halides the product formed is preferentially the one in which maximum number of alkyl groups are attached to the doubly bonded carbon atoms.
Dehydration by passing over alumina (Lewis Acid)
CH – CH
OH Al2O3 CH = CH + H O
3 2
CH3
350°C 2 2 2
Al O
CH3
2 3
250°C
CH3 – CH = CH2
(CH ) C – OH Al2O3 CH – C = CH
3 3 250°C 3 2
The experimental conditions change with the structure of alcohols
pri - alcohols
⎯⎯con⎯c. H⎯2S⎯O⎯4 → alkene
180 C
sec - alcohols
⎯⎯85%⎯H⎯3PO⎯3 →
170°C
alkene
OH ⎯8⎯5%⎯H3⎯P⎯O3→
170°C
ter - alcohols
CH2 – OH
⎯2⎯0%⎯H2⎯S⎯O4→
85°C
H+ / heat
alkene
Dehydrohalogenation of alkyl halides
β α
CH3 – CH2 – CH2 – CH2 – Br
alc KOH
Δ
CH3
– CH2
– CH = CH2
β α β
CH – CH – CH – CH
alc KOH
CH – CH = CH – CH + CH – CH – CH = CH
2. 3 2 |
3 Δ 3 3
3 2 2
Br (Major) (Minor)
CH3 CH3
CH2
| | ||
CH – CH – C – CH
alc KOH
CH3 – C – CH – CH3 + (CH3)2 C = C(CH3)2
3. 3
| 3 Δ
Br
(Minor)
|
CH3 (Major)
The base used may be strongly basic anions like OH–, RO–, C2H5O– (CH3)3CO– etc.)
The group leaving (i.e., halogen) is a good leaving group if it is the conjugate base of a strong acid. (i.e., weakly basic halide ion).
One may also use sulphonates.
Dehydrohalogenation of 2° and 3° alkyl halides follow Saytzeff’s Rule.
Exception to Saytzeff’s Rule (Hofmann Rule)
When dehydrohalogenation is carried out with potassium, tertiary butoxide there is formation of less substituted alkene.
CH3
|
(CH ) COH
CH3
CH – CH – C = CH
(CH ) CO– + CH CH C – Br 3 3
CH – CH = C
3 2 | 2
3 3 3 2
|
CH3
75°C
3
(Minor)
CH3
CH3 (Major)
Dehalogenation Reactions
| | alc | |
– C – C –
| |
Br Br
+ Zn
KOH
– C = C – + ZnBr2
VICINAL
2 R – CH
Br alc
+ Zn KOH
Br
R – CH = CH – R + 2ZnBr2
GEMINAL
By controlled hydrogenation of alkynes
(i)
CH3 – C ≡ C – CH3 + H2
Pd/BaSO4 LINDLAR’S CATALYST
CH3 C = C CH3 Cis - 2 - Butene H H
Here we may use small amounts of sulphur or quinoline also.
CH – C ≡ C – CH
Na/LiqNH3
CH3
H
C = C
3 3 Δ H
CH3
trans-2-Butene
By heating Quaternary Ammonium hydroxide
(C2H5)NOH Δ
CH2 = CH2 + (C2H5)3N + H2O
Kolbe’s Electrolysis
CH2COONa
|
CH2COONa
+ 2H2O
electrolysis
CH2 = CH2 + 2CO2 + 2NaOH + H2
Sodium succinate
Mechanism is similar to preparation of alkanes.
Pyrolysis
CH CH CH CH ⎯⎯Δ → CH –CH=CH + CH
3 2 2 3 770 K 3 2 4
CH CH CH CH CH CH ⎯⎯Δ → CH CH=CH
+ CH CH CH
3 2 2 2 2 3 770 K 3
2 3 2 3
By heating saturated hydrocarbon with SiO2
C H – CH
CH – C H ⎯⎯SiO⎯2 → C H –CH=CH–C H + H
6 5 2
2 6 5 Δ 6 5
6 5 2
Physical Properties
Solubility
They are insoluble in water but soluble in organic solvents.
Boiling point
The boiling point of cis–alkenes is usually higher than corresponding trans–alkenes (More polarity).
Melting point
The melting point of trans-alkenes is usually greater than cis-alkene. (trans form is more symmetrical).
Chemical Properties
In alkenes C = C bond is made of stable σ-bond and reactive π-bond. As π-bond can easily be broken, alkenes undergo addition reactions.
C = C
+ XY
C –
|
C
|
X
Y
Being electron rich species they react with electrophiles in three ways.
Ionic Mechanism
C = C E – Nu C – C
+
–
+ Nu
| E
Free Radical Mechanism
C = C E – E C – C + E
|
E
Transition State
C = C+ E – Nu C – C
E Nu
Reactions :
Hydrogenation :
C = C + H2
Pd or Pd or Ni Δ
C – C
H H
The relative rates of hydrogenation is CH2 = CH2 > RCH = CH2 > R2 C = CH2 > RCH = CHR > R2 C
= CR2. This is due to the fact that as number of alkyl groups increase the steric hindrance increases and there by rate decreases.
Halogenation :
X
CH = CH + X ⎯⎯⎯C⎯C⎯l4 ⎯⎯→ |
2 2 2 Or
inert solvent
CH2 – CH2
|
X
CH = CH
Cl
Cl
⎯⎯⎯C⎯C⎯l4 ⎯⎯→ |
2 2 2
Or inert solvent
CH2 – CH2
|
Cl
The addition always leads to the formation of trans addition product.
Mechanism :
δ– X
δ+ X
C = C + X2 C …— C
Transition State (T.S.)
δ–
X
C …– C C – C + X
X
| C — C
|
X
X
e.g., CH3 – CH = CH – CH3 + Cl2
– 9°C
CH3– CH – CH – CH3
| |
Cl Cl
Addition of Halogen Acid
C = C + HX
C — C
H X
The reactivity order of halogen acid is HI > HBr > HCl
Mechanism :
R–CH=CH2 + HX
b R–CH–CH2
T.S.
(a)
– R–CH–CH3 + X
–
(b) R– CH2–CH2 + X
Here the transition state cleaves to from the most stable carbocation hence (a) cleavage takes place
and hence, + – are formed
R – CH2 – CH3+ X
i.e., R – CH – CH3+ X
R – CH – CH3
| X
Markownikoff’s Rule may therefore be applied. It states that, “During the addition of unsymmetrical reagents to unsymmetrical alkenes, the negative part of the addendum goes to carbon of double bond with least number of atoms”.
Example :
δ—
X
H b
CH3–CH=CH2 + HX
(a)
CH3– CH – CH2
CH3–CH–CH3 + X A
CH3–CH2–CH2 + X
B
Since A is more stable than B. Hence A is formed and we get
+
CH3 – CH – CH3 X
CH3 – CH – CH3
| X
CH3 – CH = CH2 + HBr
CH3– CH– CH3
|
Br
Kharasch - Mayo Effect
If the above reaction is carried out in the presence of some peroxide then addition takes place contrary to Markownikoff’s Rule
CH3 – CH = CH2+ HBr
⎯P⎯ero⎯x⎯ide→ CH3– CH2 – CH2 – Br
Explanation
This can be explained on the basis of free radical formation
•
Step 1 : R – O – O – R 2R – O
• •
Step 2 : R – O + HBr ROH + Br
CH – CH – CH • (A)
| 2
Step 3 : CH3 – CH = CH2 + Br
Br 1° Carbon free radical
•
CH3 – CH – CH2 – Br (B)
(B) is more stable than (A). 2° Carbon free radical
Addition of Hypohalous Acid
C = C+ HOX
CH2 = CH2 + HOCl
CH2 – CH = CH2 + HOBr
Addition of Water
C — C OH X
CH2 — CH2
OH Cl
CH2 – CH – CH2
OH Br
This reaction also takes place via carbocation mechanism (Rearrangement possible).
CH3
(CH3)2 C = CH2 + H2O
H+ 10% H2SO4
CH3 – C – OH
CH3
Addition of cold and conc. H2SO4
Carbocation Mechanism Followed, (Rearrangement Possible)
R – CH = CH2 + H2SO4
R – CH – CH3
H2O
Heat
R – CH – CH3
HSO4 OH
Oxy-Mercuration - Demercuration
Synthesis of alcohols from alkenes is in accordance with Markownikoff’s Rule (No carbocation formed)
R – CH = CH
Hg(OAc)2/THF,H2O
R – CH – CH
2 ii) NaBH /OH– | 3
OH
Addition of Oxygen:
Ag CH2 CH2
CH2 = CH2 + ½ O2 570 K
O
Ozonolysis:
C = C + O3
O
CCl4 C
Zn/H2O
–H2O2
2 C = O
O— O
Example :
CH3CH = CH2 + O3
CCl4
O
CH — CH CH Zn/H2O
–H2O2
CH3 – CHO + HCHO
O — O
CH3
+
O
||
O3/CCl4
Zn/H2O (–H2O2)
CH3
Ozonalysis helps to locate the positions of double bonds in alkene.
Hydroboration Oxidation
R – CH = CH2 + B2H6
0°C
ether
(R – CH2 – CH2)3 – B
H2O2 OH–
R – CH2 – CH2 – OH + H3BO3
(Product is Antimarkownikov product.)
Oxidation Reactions
Reaction with Baeyer’s Reagent (Cold dilute Alkaline KMnO4, Hydroxylation)
C = C + alk KMnO C – C
| |
OH OH
The addition is a syn addition to form vicinal dihydroxy compounds.
With hot KMnO4 or acidic KMnO4
CH2 = CH2
⎯⎯[O⎯] →
Hot KMnO 4
2HCOOH ⎯⎯→ 2CO2 + 2H2O
CH3 − CH = CH2 ⎯⎯KM⎯nO⎯4 →CH3COOH + CO2 + H2O
H
(CH ) C = C(CH ) ⎯⎯Ho⎯t → 2 CH3
3 2 3 2 KMnO4
CH3
C = O
Substitution Reaction
CH3–CH = CH2 + Cl2 ⎯⎯500⎯−60⎯0⎯°C →
Cl–CH2–CH=CH2 + HCl–
This type of reaction takes place at a carbon atom attached to double bond carbon. This is called allylic substitution.
Mechanism
Step - 1 : Cl – Cl
⎯5⎯00 ⎯−60⎯0⎯°C→ 2Cl•
Step - 2 : CH =CH–CH
+Cl•
HCl + CH
= CH–
CH•
2 3 ⎯⎯→ 2 2
Step - 3 : CH2
= CH -
CH• +Cl2
⎯⎯→
CH2
= CH – CH2
Cl + Cl•
Wohl Zeigler Reaction
CH3 – CH = CH2 + Br2
⎯L⎯ow ⎯con⎯c. o⎯f B⎯r2→
CH2 = CH–CH2–Br
The low concentration of Br2 is obtained from NBS
O
|| CH3 – CH = CH2 +CH2 — C
CH2 — C
|| O
N – Br
CH2 = CH – CH2Br +
O
||
CH2 — C
|
CH2 — C
||
O
N – H
Addition of Carbenes
(i)
CH2 – N ≡ N
hν ..
CH2 + N2
(ii) CH3 – CH = CH2 +
Isomerization :
C&H2 ⎯⎯h⎯ν → CH3 – CH – CH2
CH2
CH – CH – CH – CH = CH
700 - 970 atm
CH – CH – CH = CH – CH
2 2 2
Polymerization :
2 or Al2 (SO4)3; 470 K
3 2 3
CH = CH Pressure
O2
( CH2 – CH2)n
CF2 = CF2
Trans O2
( F2C – CF2)n
ALKYNES
Compounds containing the structural unit – C≡C– are called Alkynes. Like the double bond it is unsaturated and highly reactive towards the reagent that double bonds react with and also towards others. The simplest member of the alkyne family is acetylene, C2H2.Each of the carbon atoms carrying the triple bond are sp hybridized.
1s 2s 3p
C
sp
C
sp
Alkynes the compounds having general formula CnH2n – 2 where n ≥ 2 it can be categorize by two ways.
Terminal alkynes : Alkynes having triple bond at one end of the carbon attached to H
e.g. CH3–C ≡ C–H, CH3 – CH2–C≡CH. Terminal hydrogen is acidic in nature.
Non-terminal alkynes : Alkynes in which both triple bonded carbons are attached to alkyl group.
Preparation of Alkynes
From Dehydrohalogenation of vicinal or geminal dihalides
CH2
|
— CH2
|
alc. KOH
Δ
CH ≡ CH + 2H2O + KBr
Br Br
R– CH – CH alc. KOH
R – C ≡ CH + 2H O + KBr
| | 2 Δ 2
Br Br
Dehalogenation Reaction
(a)
X X
| |
– C – C –
| |
X X
Zn dust
Δ
– C ≡ C + 2ZnX2
X
2R – C X
X
Zn dust
Δ
R – C ≡ C – R + 3ZnX2
Kolbe’s Electrolytic Decarboxylation
R COOK
C
|| C
R COOK
+ 2H O Electrolysis
R – C ≡ C – R + 2KOH + CO2 + H2
cis or trans
Formation of Higher alkyne
CH ≡ CH NaNH2
CH ≡ C Na
CH ≡ C Na + CH3Cl CH ≡ C – CH3 + NaCl
R–C ≡ CH + NaNH2 RC ≡ CNa + NH3
R–C ≡ C Na + R′ X R–C ≡ C–R′ + NaX
Chemical Properties
Alkynes undergo electrophilic addition generally but in the presence of salt of heavy metals which forms complexes with multiple bonds it undergo nucleophilic addition reaction.
Addition Reaction
Electrophilic addition reaction :
Addition of halogen
CH
+ Cl2
CH
CHCl = CHCl Cl2
acetylene dichloride
CHCl2
CHCl2
acetylene tetrachloride (westron)
CH3 – C ≡ CH
Br2/CCl4
CH3 – C = C
Br
Br Br2/CCl4
H
Br Br CH3 – C – C – H
Br Br
Trans-1, 2-dibromopropene
1, 1, 2, 2-tetra bromo propane
Addition of halogen acids
HC ≡ CH HCl CH = CHCl
HCl CH CHCl
CH3COOH
2
Vinyl chloride
CH3COOH
2 2
Ethylidene chloride
CH ≡ CH
Cl2/H2O
or
CH = CHOH
OH
HOCl CHCl – CH – OH
–H2O
HCCl2 – CHO
HOCl Cl
Dichloro acetaldehyde
Nucleophilic addition reaction :
Because of greater electronegativity of sp hybridized C as compared to sp2 hybridized carbons, Alkynes are more susceptible to nucleophilic addition reactions than alkenes. It is due to formation of some
sort of complex of heavy metal ion with π electrons like
Hg2+
and this results decrease in
electron density around triply bonded carbon atoms and this can be attacked by nucleophiles.
Addition of H2O or hydration of alkyne or Kucherov reaction
+ 2+
H , Hg
H OH O
tautomerise
+ H2O
CH
333 K
H – C = C – H
Vinyl alcohol
CH3 – C – H
Acetaldehyde
R – C ≡ C – H + H2O
Addition of HCN
+ 2+
H , Hg
OH
R – C = CH2
tautomerise
O
R – C – CH3
Ketone
CH + HCN Ba(CN)2
CH
CH2
CHCN
Vinyl cyanide
Similarly alkynes adds acids in presence of lewis acid catalyst or Hg2+ give vinyl ester.
O
HC≡C – H + H3CCOOH
Hg2+/353 H
CH3 – C – O – CH = CH2
Vinyl ethanoate
O O R
R – C
≡ CH + CH – C – OH BF3 CH – C – O – C = CH
a-alkyl vinyl ethanoate
Reaction of Acidic H Atom
Alkynes having acidic H atom reacts with metals like Na, K, evolves H2 gas.
CH
+ Na
CH (1 mol)
C – Na
C – H
+ 1/2 H2↑
CNa C – H
+ Na
Monosodium acetylide
C – Na
+ 1/2 H2↑
C – Na
Disodium acetylide
HC ≡ C − H + NaNH2 → HC ≡ C − Na + NH3 ↑ ⎯⎯NaN⎯H⎯2 →NaC ≡ C − Na + NH3 ↑
Reaction with Tollens reagent : When alkyne reacts with tollens reagent (Ammonical AgNO3 solution) at forms white precipitate of silver acetylide.
C – H
C – H
+ 2AgNO3 + 2NH4OH
(Tollens reagent)
C – Ag C – Ag
¯ + 2NH4Cl + 2H2O
(White precipitate)
These acetylide are not decomposed by H2O like acetylide of Na but by mineral acids like dil HNO3.
C – Ag C – Ag
+ 2HNO3
CH
2AgNO3 +
CH
R − C ≡ CH + Ag+ → R − C ≡ C − Ag + H⊕
Reaction with Ammonical Cuprous Chloride :
HC
+ Cu2Cl2 + 2NH4OH
HC
CCu
CCu
(red ppt)
↓+ 2NH4Cl + 2H2O
copper acetylide
These reactions are used to distinguish terminal alkynes from other alkynes.
Polymerization Reaction
When acetylene is passed in red hot cutube or retube. It converted into benzene.
CH 773K
3
CH
C6H6
CH3
Similarly CH3 – C ≡ CH
red hot Cu or Fe tube
H3C
CH3
(Mesitylene)
CH
2
CuCl/NH4Cl
CH = CH – C ≡ CH
HCl
Cl
CH = CH – C = CH
CH Cu2Cl2/NH4Cl
2
Vinyl acetylene
2 2
Chloroprene
Chloroprene on polymerization gives polymer called neoprene; used as artificial rubber.
Under high pressure and in presence Ni(CN)2 acetylene tetramerises.
4 CH ≡ CH
Ni(CN)2
Cycloocta tetraene
Reaction with S8, N2, NH3 and HCN
Acetylene reacts with S8, N2, NH3 and HCN to form different heterocyclic compounds.
CH
CH
CH
+
+ CH
300°C
S
CH
CH
+ N2
Electric spark
2HCN
1 S
(Thiophene)
8 8
CH CH Δ
+
CH + CH N
(iv)
2 CH + HCN red hot tube
CH
N
(Pyridine)
NH3
H
(Pyrole)
AROMATIC HYDROCARBONS
Hydrocarbons which follow Huckel rule are termed as Aromatic hydrocarbons.
Huckel's rule :
A planar molecule having complete delocalisation of (4n + 2) π electrons is termed as aromatic hydrocarbon (where n is any integer)
e.g., 4n + 2 = 6
n = 1
⊕
4n + 2 = 2
n = 0
4n + 2 = 6
n = 1
CH3
4n + 2 = 6
n = 1
4n + 2 = 6
n = 1
Homologues of Benzene
They are all aromatic hydrocarbons. Aromaticity is present due to benzene ring.
CH3 C2H5
etc.
Electrophilic Aromatic substitution reactions in Benzene : (EAS)
Benzene and its homologues readily undergo EAS. As a consequence of complete delocalization of π
electrons in benzene, it has π electron cloud over benzene ring which makes electrophile attack over it.
General Mechanism :
+ E+
H
+
E E + H+
Halogenation
+ Cl
(resonance stabilised intermediate)
Cl
⎯⎯FeC⎯l3 →
+ HCl
Benzene
2 dark
Reaction with I2 is reversible.
I
+ I2
+ HI
Hence it is carried out in the presence of conc. nitric acid to oxidise the Hydrogen Iodide formed.
Nitration
+ HNO3
⎯⎯H2S⎯O4⎯co⎯n⎯c. →
NO2
H2O
⎯⎯H2S⎯O4⎯co⎯n⎯c. →
+HNO3 363−373K
NO2
NO2
Sulphonation
Nitro benzene
SO3H
SO3H
+ H2SO4 + SO3
⎯⎯He⎯at →
+ H2O or + ClSO3H
⎯⎯He⎯at →
ΗCl
Friedel Crafts Reaction
Chloro Sulphuric Acid Benzene sulphonic acid
Alkylation : Reactive intermediate is carbocation which can undergo rearrangement.
CH3
+ CH3 – Cl
⎯⎯Anh⎯ydr⎯ous⎯Al⎯C⎯l3 →
+ HCl
+ CH3CH2CH2Cl
⎯⎯Anh⎯ydr⎯ous⎯Al⎯C⎯l3 →
+ HCl
⎛ O:
⎜
Acylation : Reactive intermediate is acylium ion ⎝R–C+
COCH3
which cannot undergo rearrangement.
+ CH3 – COCl
⎯⎯Anh⎯ydr⎯ous⎯Al⎯C⎯l3 →
+ HCl
Acetyl chloride Acetophenone
Ortho and para substitution : Electron releasing groups like - R (alkyl) — O.. H, — O.. R, — NHR,
— NHCOR are activating groups i.e., they increase electron density at ortho and para position,
therefore, are ortho and para directing towards electrophilic substitution reactions.
Meta substitution : Electron withdrawing groups such as – NO2, – CHO, – COOH, – COCH3, – CN,
– SO3H, – COOR are called deactivating groups. They decrease electron density at ortho and para- position, therefore, electrophillic substitution takes place at meta-position.
Halogenation of side chain :
CH3
Toluene
or Methyl Benzene
+ Cl
⎯⎯su⎯n →
2 light
CH2Cl
Benzyl chloride
or chlorophenyl methane
+ Cl2
⎯⎯hv →
CHCl2
Benzal chloride
or dichlorophenyl methane
⎯⎯C⎯l2 →
CCl3
+ HCl
Benzotrichloride
Oxidation :
or trichlorophenyl methane
O O
Benzene
+ 5O2
+ H2O
2-Butene-1,4-dioic acid
❑ ❑ ❑
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